x^2-7x+48=0

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Solution for x^2-7x+48=0 equation:


Simplifying
x2 + -7x + 48 = 0

Reorder the terms:
48 + -7x + x2 = 0

Solving
48 + -7x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-48' to each side of the equation.
48 + -7x + -48 + x2 = 0 + -48

Reorder the terms:
48 + -48 + -7x + x2 = 0 + -48

Combine like terms: 48 + -48 = 0
0 + -7x + x2 = 0 + -48
-7x + x2 = 0 + -48

Combine like terms: 0 + -48 = -48
-7x + x2 = -48

The x term is -7x.  Take half its coefficient (-3.5).
Square it (12.25) and add it to both sides.

Add '12.25' to each side of the equation.
-7x + 12.25 + x2 = -48 + 12.25

Reorder the terms:
12.25 + -7x + x2 = -48 + 12.25

Combine like terms: -48 + 12.25 = -35.75
12.25 + -7x + x2 = -35.75

Factor a perfect square on the left side:
(x + -3.5)(x + -3.5) = -35.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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